User:John R. Brews/Coriolis force: Difference between revisions

From Citizendium
Jump to navigation Jump to search
imported>John R. Brews
No edit summary
imported>John R. Brews
Line 8: Line 8:
:<math>\boldsymbol{ a}_C =-2\boldsymbol{\Omega \times v}= 2\,\omega\, \begin{pmatrix} v_n \sin \varphi-v_u \cos \varphi \\ -v_e \sin \varphi \\ v_e \cos\varphi\end{pmatrix}\ .</math>
:<math>\boldsymbol{ a}_C =-2\boldsymbol{\Omega \times v}= 2\,\omega\, \begin{pmatrix} v_n \sin \varphi-v_u \cos \varphi \\ -v_e \sin \varphi \\ v_e \cos\varphi\end{pmatrix}\ .</math>


When considering atmospheric or oceanic dynamics, the vertical velocity is small and the vertical component of the Coriolis acceleration is small compared to gravity. For such cases, only the horizontal (East and North) components matter. The restriction of the above to the horizontal plane is (setting <font style="font-family: Book Antiqua; font-size:100%; font-style:italic; font-weight:normal;">v<sub>u</sub></font>=0):
When considering atmospheric or oceanic dynamics, the vertical velocity is small and the vertical component of the Coriolis acceleration is small compared to gravity. For such cases, only the horizontal (East and North) components matter. The restriction of the above to the horizontal plane is (setting ''v<sub>u</sub>''=0):


:<math> \boldsymbol{ v} = \begin{pmatrix} v_e \\ v_n\end{pmatrix}\ ,</math> &nbsp; &nbsp; <math>\boldsymbol{ a}_c = \begin{pmatrix} v_n \\ -v_e\end{pmatrix}\ f\ , </math>
:<math> \boldsymbol{ v} = \begin{pmatrix} v_e \\ v_n\end{pmatrix}\ ,</math> &nbsp; &nbsp; <math>\boldsymbol{ a}_c = \begin{pmatrix} v_n \\ -v_e\end{pmatrix}\ f\ , </math>


where <math>f = 2 \omega \sin \varphi \,</math> is called the Coriolis parameter.
where ''f'' = {{nowrap|2''&omega;'' sin''&phi;''}} is called the ''Coriolis parameter''.


By setting ''v<sub>n</sub>'' = 0, it can be seen immediately that (for positive φ and ω) a movement due east results in an acceleration due south. Similarly, setting ''v<sub>e</sub>'' = 0, it is seen that a movement due north results in an acceleration due east. In general, observed horizontally, looking along the direction of the movement causing the acceleration, the acceleration always is turned 90° to the right and of the same size regardless of the horizontal orientation. That is:<ref name=Canterbury>{{Cite web|url = http://www.phys.canterbury.ac.nz/newsletter/2005/nl20051202.pdf|author = David Morin, Eric Zaslow, Elizabeth Haley, John Goldne, and Natan Salwen|title = Limerick – May the Force Be With You|work = Weekly Newsletter Volume 22, No 47|publisher = Department of Physics and Astronomy, University of Canterbury|date = 2 December 2005|accessdate = 2009-01-01}}</ref><ref name=Morin>{{Cite book|author=David Morin |url=http://books.google.com/?id=Ni6CD7K2X4MC&pg=PA466&dq=Coriolis+carousel |title=Introduction to classical mechanics: with problems and solutions |page= 466 |isbn= 0521876222 |year=2008 |publisher=Cambridge University Press}}</ref>
By setting ''v<sub>n</sub>'' = 0, it can be seen immediately that (for positive φ and ω) a movement due east results in an acceleration due south. Similarly, setting ''v<sub>e</sub>'' = 0, it is seen that a movement due north results in an acceleration due east. In general, observed horizontally, looking along the direction of the movement causing the acceleration, the acceleration always is turned 90° to the right and of the same size regardless of the horizontal orientation. That is:<ref name=Canterbury>{{Cite web|url = http://www.phys.canterbury.ac.nz/newsletter/2005/nl20051202.pdf|author = David Morin, Eric Zaslow, Elizabeth Haley, John Goldne, and Natan Salwen|title = Limerick – May the Force Be With You|work = Weekly Newsletter Volume 22, No 47|publisher = Department of Physics and Astronomy, University of Canterbury|date = 2 December 2005|accessdate = 2009-01-01}}</ref><ref name=Morin>{{Cite book|author=David Morin |url=http://books.google.com/?id=Ni6CD7K2X4MC&pg=PA466&dq=Coriolis+carousel |title=Introduction to classical mechanics: with problems and solutions |page= 466 |isbn= 0521876222 |year=2008 |publisher=Cambridge University Press}}</ref>

Revision as of 12:39, 5 March 2011

(PD) Image: John R. Brews
Coordinate system at latitude φ with x-axis east, y-axis north and z-axis upward (that is, radially outward from center of sphere).

Rotating sphere

Consider a location with latitude φ on a sphere that is rotating around the north-south axis.[1] A local coordinate system is set up with the x axis horizontally due east, the y axis horizontally due north and the z axis vertically upwards. The rotation vector, velocity of movement and Coriolis acceleration expressed in this local coordinate system (listing components in the order East (e), North (n) and Upward (u)) are:

   

When considering atmospheric or oceanic dynamics, the vertical velocity is small and the vertical component of the Coriolis acceleration is small compared to gravity. For such cases, only the horizontal (East and North) components matter. The restriction of the above to the horizontal plane is (setting vu=0):

   

where f = 2ω sinφ is called the Coriolis parameter.

By setting vn = 0, it can be seen immediately that (for positive φ and ω) a movement due east results in an acceleration due south. Similarly, setting ve = 0, it is seen that a movement due north results in an acceleration due east. In general, observed horizontally, looking along the direction of the movement causing the acceleration, the acceleration always is turned 90° to the right and of the same size regardless of the horizontal orientation. That is:[2][3]

On a merry-go-round in the night

Coriolis was shaken with fright
Despite how he walked
'Twas like he was stalked
By some fiend always pushing him right

—David Morin, Eric Zaslow, E'beth Haley, John Golden, and Nathan Salwen

As a different case, consider equatorial motion setting φ = 0°. In this case, Ω is parallel to the North or n-axis, and:

      

Accordingly, an eastward motion (that is, in the same direction as the rotation of the sphere) provides an upward acceleration known as the Eötvös effect, and an upward motion produces an acceleration due west.

Notes

  1. William Menke & Dallas Abbott (1990). Geophysical Theory. Columbia University Press, 124–126. ISBN 0231067925. 
  2. David Morin, Eric Zaslow, Elizabeth Haley, John Goldne, and Natan Salwen (2 December 2005). Limerick – May the Force Be With You. Weekly Newsletter Volume 22, No 47. Department of Physics and Astronomy, University of Canterbury. Retrieved on 2009-01-01.
  3. David Morin (2008). Introduction to classical mechanics: with problems and solutions. Cambridge University Press. ISBN 0521876222. 

Contributed by myself in June 2008, for example, here here, added Limerick


http://books.google.com/books?id=-3H5V0LGBOgC&pg=PA122&dq=Foucault+pendulum&hl=en&ei=CV1gTenZOpGisQO9ruzNCA&sa=X&oi=book_result&ct=result&resnum=9&ved=0CGQQ6AEwCA#v=onepage&q=Foucault%20pendulum&f=false

http://books.google.com/books?id=NAo7yv7Jmq0C&pg=PA22&dq=Foucault+pendulum&hl=en&ei=VopgTdmBCoK4sQP6p-ncCA&sa=X&oi=book_result&ct=result&resnum=1&ved=0CCoQ6AEwADgK#v=onepage&q=Foucault%20pendulum&f=false

http://books.google.com/books?id=NAo7yv7Jmq0C&pg=PA22&dq=Foucault+pendulum&hl=en&ei=VYVgTcujHoOusAO0vOXNCA&sa=X&oi=book_result&ct=result&resnum=1&ved=0CCoQ6AEwADgK#v=onepage&q=Foucault%20pendulum&f=false


http://books.google.com/books?id=hrBe52GPHrYC&pg=PA351&dq=Foucault+pendulum&hl=en&ei=VYVgTcujHoOusAO0vOXNCA&sa=X&oi=book_result&ct=result&resnum=9&ved=0CFQQ6AEwCDgK#v=onepage&q=Foucault%20pendulum&f=false

http://books.google.com/books?id=GfCil84YTm4C&pg=PA116&dq=Foucault+pendulum&hl=en&ei=E4ZgTeaDGIa-sQP1zvDHCA&sa=X&oi=book_result&ct=result&resnum=8&ved=0CE0Q6AEwBzgU#v=onepage&q=Foucault%20pendulum&f=false

http://books.google.com/books?id=mms6MXH9CuoC&pg=PA22&dq=Foucault+pendulum&hl=en&ei=34ZgTeukEIuesQPMvPHYCA&sa=X&oi=book_result&ct=result&resnum=2&ved=0CCsQ6AEwATge#v=onepage&q=Foucault%20pendulum&f=false

http://books.google.com/books?id=imrm2aOs9_8C&pg=PA90&dq=Foucault+pendulum&hl=en&ei=34ZgTeukEIuesQPMvPHYCA&sa=X&oi=book_result&ct=result&resnum=7&ved=0CEQQ6AEwBjge#v=onepage&q=Foucault%20pendulum&f=false

Maxwell

http://books.google.com/books?id=wr2QOBqOBakC&pg=PA184&dq=Foucault+pendulum&hl=en&ei=U4hgTd-9Foa6sQP3lt3ACA&sa=X&oi=book_result&ct=result&resnum=2&ved=0CDAQ6AEwATgy#v=onepage&q=Foucault%20pendulum&f=false

Practical matters

http://books.google.com/books?id=sSPLspTUYEEC&pg=PA73&dq=Foucault+pendulum&hl=en&ei=U4hgTd-9Foa6sQP3lt3ACA&sa=X&oi=book_result&ct=result&resnum=4&ved=0CDsQ6AEwAzgy#v=onepage&q=Foucault%20pendulum&f=false

http://books.google.com/books?id=1J2hzvX2Xh8C&pg=PA272&dq=Foucault+pendulum&hl=en&ei=D4lgTdrSGIi6sQPrsunYCA&sa=X&oi=book_result&ct=result&resnum=3&ved=0CDIQ6AEwAjg8#v=onepage&q=Foucault%20pendulum&f=false

References